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Thursday 13 September 2012

UVA - 11547 - Automatic Answer

#include <stdio.h>

int main()
{   int x=0,t=0,i=0;
    long sum=0;
    scanf("%d",&t);
    for(i=0;i<t;i++){
        scanf("%d",&x);
        sum=abs((((x*63)+7492)*5)-498);
        printf("%d\n",(sum/10)%10);
    }
    return 0;
}

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